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The minimum force required to start pushing a body up a rough (frictional coefficient μ) inclined plane F1 while the minimum force needed to prevent it from sliding down is F2. If the inclined plane makes an angle θ from the horizontal such that tan θ= 2μ then the ratio F1/F2 is (a) 4 (b) 1 (c) 2 (d) 3

Harshit Singh , 4 Years ago
Grade 12th pass
anser 1 Answers
Pawan Prajapati

Last Activity: 4 Years ago

Answer ::

We have to work against the sliding force due to gravity and frictional force to push upwards. Therefore, the force F1= mgsinθ + μmgcosθ.

To stop the body from sliding work is done against sliding force but frictional force stops the body from sliding.
Therefore, the force F2= mgsinθ – μmgcosθ.
F1/F2 = mgsinθ + μmgcosθ/ mgsinθ – μmgcosθ
F1/F2 = tanθ +μ / tanθ – μ
(since tanθ = 2μ)
F1/F2 =2μ +μ /2μ – μ
F1/F2 = 3
Answer: (d) 3


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