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`        The maximum velocity of a particle executlng SHM Is v.if the amplitude ls doubled and the time period of oscillation deceased to 1/3 of Its original value, the maximum velocity becomes (1) 18v (2) 12v (3)6V (4)3v Explain?`
3 years ago

## Answers : (1)

Vikas TU
11770 Points
```							Maximum velocity = > V = Aw...............(1)After the Time period decreased to 1/3rd of its original value.Hence, w’ = 3wtherfore,V’ = 2A*3w => 6Aw...............(2)Divding the eqns. we get,V’ = 6V is the answer.
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions