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The maximum velocity of a particle executlng SHM Is v.if the amplitude ls doubled and the time period of oscillation deceased to 1/3 of Its original value, the maximum velocity becomes (1) 18v (2) 12v (3)6V (4)3v Explain?

The maximum velocity of a particle executlng SHM Is v.if the amplitude ls doubled and the time period of oscillation deceased to 1/3 of Its original value, the maximum velocity becomes (1) 18v (2) 12v (3)6V (4)3v Explain?

Grade:11

1 Answers

Vikas TU
14149 Points
7 years ago
Maximum velocity = > V = Aw...............(1)
After the Time period decreased to 1/3rd of its original value.
Hence, w’ = 3w
therfore,
V’ = 2A*3w => 6Aw...............(2)
Divding the eqns. we get,
V’ = 6V is the answer.
 
 

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