Flag Mechanics> The maximum speed and acceleration of a p...
question mark

The maximum speed and acceleration of a particle executing simple harmonic motion are 10 cm s-1 and 50 cm s-2. Find the position(s) of the particle when the speed is 8 cm s-1.

Amit Saxena , 11 Years ago
Grade upto college level
anser 1 Answers
Navjyot Kalra
Sol. vmax = 10 cm/sec. ⇒ rω = 10 ⇒ ω2 = 100/r2 ….(1) Amax = ω2r = 50 cm/sec ⇒ ω2 = 50/y = 50/r …..(2) ∴ 100/r2 = 50/r ⇒ r = 2 cm. ∴ ω = √(100/r^2 ) = 5 sec2 Again, to find out the positions where the speed is 8m/sec, v2 = ω2 (r2 – y2) ⇒ 64 = 25 ( 4 – y2) ⇒ 4 – y2 = 64/25 ⇒ y2 = 1.44 ⇒ y = √1.44 ⇒ y = ± 1.2 cm from mean position.
Last Activity: 11 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments