The maximum range of a bullet fired from a toy pistol mounted on a car at rest is 40m. What will be acute angle of inclination of pistol for max. Range when the car is moving in the direction f firing with uniform velocity v=20m/s, not the horizontal surface?

Question

Akshat Kumar tripathi · Answer

We have Range of a projectile = u^2 sin 2theta/g Therefore, u^2 sin 2 theta /g = 40400*sin 2 theta /10 = 40 Hence, theta = 45 degree

K · Answer

u^2/g = 100 => u = 20 m/s t = 2ugsina and R = (ucosa+20)(2usina/g) Put dR/da = 0 => cosa = ½ => a = 60°.

Deepika Pant · Answer

The initial velocity,

Anagha · Answer

when at rest, the range of the projectile is u 2 sin(2x) / g. This is maximum when sin(2x)=1. So, 40 = u 2 / g => u = 20 Now, as the car is moving with 20 m/s, the initial velocity of the projectile in the x direction is (20 + u cos(x)). As acceleration along the x direction is zero, range is T * V => (2u sin(x) / g)* (20 + u cos(x)) on differentiating and equating to zero (to get the maximum) we get x =60 Hope that helps!

ankit singh · Answer

g u 2 ​ = 1 0 0 ⇒ u = 2 0 m / s t = g 2 u sin θ ​ and R = ( u cos θ + 2 0 ) ( g 2 u sin θ ​ ) Put d θ d R ​ = 0 ⇒ cos θ = 1 / 2 ⇒ θ = 6 0 ∘ . ankit singh nt bhpal thanks and regards

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The maximum range of a bullet fired from a toy pistol mounted on a car at rest is 40m. What will be acute angle of inclination of pistol for max. Range when the car is moving in the direction f firing with uniform velocity v=20m/s, not the horizontal surface?

The maximum range of a bullet fired from a toy pistol mounted on a car at rest is 40m. What will be acute angle of inclination of pistol for max. Range when the car is moving in the direction f firing with uniform velocity v=20m/s, not the horizontal surface?

5 Answers

gu2=100
⇒u=20 m/s
t=g2usinθ
and R=(ucosθ+20)(g2usinθ)
Put dθdR=0
⇒cosθ=1/2
⇒θ=60∘.

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The maximum range of a bullet fired from a toy pistol mounted on a car at rest is 40m. What will be acute angle of inclination of pistol for max. Range when the car is moving in the direction f firing with uniform velocity v=20m/s, not the horizontal surface?

The maximum range of a bullet fired from a toy pistol mounted on a car at rest is 40m. What will be acute angle of inclination of pistol for max. Range when the car is moving in the direction f firing with uniform velocity v=20m/s, not the horizontal surface?

5 Answers

gu2​=100⇒u=20 m/st=g2usinθ​and R=(ucosθ+20)(g2usinθ​)Put dθdR​=0⇒cosθ=1/2⇒θ=60∘.

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gu2=100
⇒u=20 m/s
t=g2usinθ
and R=(ucosθ+20)(g2usinθ)
Put dθdR=0
⇒cosθ=1/2
⇒θ=60∘.