Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
The maximum range of a bullet fired from a toy pistol mounted on a car at rest is 40m. What will be acute angle of inclination of pistol for max. Range when the car is moving in the direction f firing with uniform velocity v=20m/s, not the horizontal surface?
We have Range of a projectile = u^2 sin 2theta/g Therefore, u^2 sin 2 theta /g = 40400*sin 2 theta /10 = 40 Hence, theta = 45 degree
u^2/g = 100=> u = 20 m/s t = 2ugsina and R = (ucosa+20)(2usina/g)Put dR/da = 0 => cosa = ½=> a = 60°.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -