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Grade: 12
        The maximum range of a bullet fired from a toy pistol mounted on a car at rest is 40m. What will be acute angle of inclination of pistol for max. Range when the car is moving in the direction f firing with uniform velocity v=20m/s, not the horizontal surface?
10 months ago

Answers : (2)

Akshat Kumar tripathi
42 Points
							We have Range of a projectile = u^2 sin 2theta/g     Therefore,  u^2 sin 2 theta /g = 40400*sin 2 theta /10  = 40  Hence, theta = 45 degree
						
10 months ago
K
13 Points
							
     u^2/g = 100
=> u = 20 m/s
 
t = 2ugsina and R = (ucosa+20)(2usina/g)
Put dR/da = 0 => cosa = ½
=> a = 60°.
2 months ago
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