The maximum possible acceleration of a train starting from rest and moving on straight track is 10m/s^2 and maximum possible retardation is 5m/s^2. The maximum speed that train can achieve is 85m/s. Minimum time in which the train can complete a journey of 1000m ending at rest, is n*(sqrt2)/(sqrt3) sec, where n is integer. Find n?

Himesh , 6 Years ago

Grade 11