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the max range of a particle with certain Speed on a horizontal plane is R. find the max range when projected on an incline with inclination of 30°

Anupam , 6 Years ago
Grade 11
anser 1 Answers
Eshan

Last Activity: 6 Years ago

Dear student,

Range of projectile is given asR=\dfrac{2u^2sin\theta cos\theta}{g}

Range is maximum for\theta=45^{\circ}

Therefore,\dfrac{R'}{R}=\dfrac{sin30^{\circ}cos30^{\circ}}{sin45^{\circ}cos45^{\circ}}=\dfrac{\sqrt{3}}{2}
\implies R'=\dfrac{\sqrt{3}R}{2}

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