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Grade: 11

                        

the max range of a particle with certain Speed on a horizontal plane is R. find the max range when projected on an incline with inclination of 30°

2 years ago

Answers : (1)

Eshan
askIITians Faculty
2095 Points
							Dear student,

Range of projectile is given asR=\dfrac{2u^2sin\theta cos\theta}{g}

Range is maximum for\theta=45^{\circ}

Therefore,\dfrac{R'}{R}=\dfrac{sin30^{\circ}cos30^{\circ}}{sin45^{\circ}cos45^{\circ}}=\dfrac{\sqrt{3}}{2}
\implies R'=\dfrac{\sqrt{3}R}{2}
2 years ago
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