Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
The magnitude of force acting on a particle moving along x-axis varies with time(t) as shown in figure. If at t =0 the velocity of particle is V 0 , then its velocity at t= T 0 will be The magnitude of force acting on a particle moving along x-axis varies with time(t) as shown in figure. If at t =0 the velocity of particle is V0, then its velocity at t= T0 will be
v=v^0+gT^0 is a parabola and a semicircle and are similar and this might just be like a projectile motion. The answer is vnot plus pie font tnot upon 4m. The center of mass for a system of independently moving particles still has meaning and is useful in analyzing the interactions between the particles in the system.
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -