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`        The initial speed of a bullet fired from a rifle is 630 m/s. The rifle is fired at the centre of a target 700 m away at the same level as the target. How far above the centre of the target ?`
2 years ago

Rahul Pattankar
24 Points
```							We know that y=(xtan theta)-(gx^2)/2u^2cos^2theta.....(i) T=distance in x direction/speed in x direction=>T=700/630=>T=1.11Now according to trajectory of projectile,x=(u cos theta) TPutting x in (i)y=(u cos theta) T tan theta - (g u^2 cos^2 theta T^2)/2u^2 cos^2 thetaAs projectile is projected from a height with angle zero with x direction theta=0=>y=gT^2/2=>y=10×1.11×1.11/2=>y=5×1.11×1.11=>y=6.1m
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions