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Grade 11Mechanics

The inclined surfaces of two movable wedges of same mass M are smoothly conjugated with the horizontal plane as shown in the fig. A washer of mass,M slides down the left wedge from a height h. FIND VELOCITY OF LEFT WEDGE JUST AFTER WHEN BOCK LEFT THE WEDGE.

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4 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To determine the velocity of the left wedge just after the washer leaves it, we can apply the principles of conservation of momentum and energy. This scenario involves two movable wedges and a washer sliding down one of the wedges, which creates an interesting dynamic due to the interaction between the washer and the wedges.

Understanding the System

We have two wedges, each with mass M, and a washer of mass M sliding down the left wedge from a height h. When the washer slides down, it gains kinetic energy, and as it leaves the wedge, it will impart some momentum to the wedge itself. The key here is to analyze the system just at the moment the washer leaves the wedge.

Applying Conservation of Momentum

Before the washer leaves the wedge, the system is at rest. Therefore, the total initial momentum of the system is zero. When the washer slides down and leaves the wedge, we can denote the velocity of the washer just before it leaves as v_w and the velocity of the left wedge as v_L. According to the conservation of momentum:

  • Initial momentum = Final momentum
  • 0 = M * v_w + M * v_L

From this equation, we can express the velocity of the left wedge:

M * v_w + M * v_L = 0

v_L = -v_w

Calculating the Velocity of the Washer

Next, we need to find the velocity of the washer just before it leaves the wedge. As the washer slides down from a height h, it converts its potential energy into kinetic energy. The potential energy at the top is given by:

PE = M * g * h

Where g is the acceleration due to gravity. As the washer reaches the bottom, all this potential energy will have converted into kinetic energy (assuming no friction losses):

KE = (1/2) * M * v_w^2

Setting the potential energy equal to the kinetic energy gives us:

M * g * h = (1/2) * M * v_w^2

We can simplify this equation by canceling M from both sides (assuming M is not zero):

g * h = (1/2) * v_w^2

Now, solving for v_w:

v_w^2 = 2 * g * h

v_w = sqrt(2 * g * h)

Finding the Velocity of the Left Wedge

Now that we have the velocity of the washer just before it leaves the wedge, we can substitute this back into our equation for v_L:

v_L = -v_w = -sqrt(2 * g * h)

This negative sign indicates that the left wedge moves in the opposite direction to the washer's motion. Thus, the velocity of the left wedge just after the washer leaves it is:

v_L = -sqrt(2 * g * h)

Summary

In summary, by applying the principles of conservation of momentum and energy, we determined that the velocity of the left wedge just after the washer leaves it is equal to the negative square root of twice the product of gravitational acceleration and the height from which the washer descends. This analysis showcases the interplay between potential and kinetic energy in a dynamic system.