Grade 11Mechanics

The inclined surfaces of two movable wedges of same mass M are smoothly conjugated with the horizontal plane as shown in the fig. A washer of mass,M slides down the left wedge from a height h. To what maximum height will the washer rise along the right wedge? Neglect friction

Question image for The inclined surfaces of two movable wedges of sam

Pranav Arora

9 Years agoGrade 11

1 Answer

Vikas TU

9 Years ago

The maximum height it would rise =>

let h be the height of wedges.

Now for first wedge momentum conservation and from energy conswrvation,

0 + 0 = mv1 - Mv2

we get v2 = mv1/M m/s.

and

mgh = 0.5Mv2^2 + 0.5mv1^2

solving both we get

v1^2 = 2Mgh/(M+m) …..................(1)

For wedge (2)

0.5mv1^2 = 0.5Mv0^2 + mgx

and

mv1 = Mv0

solving we get,

x = v1^2(M – m)/2gM

substituing from eq. (1)

we get

x = [(M-m)/(M+m)]h meter.

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The inclined surfaces of two movable wedges of same mass M are smoothly conjugated with the horizontal plane as shown in the fig. A washer of mass,M slides down the left wedge from a height h. To what maximum height will the washer rise along the right wedge? Neglect friction

Pranav Arora

1 Answer

Vikas TU

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