Vikas TU
Last Activity: 8 Years ago
The maximum height it would rise =>
let h be the height of wedges.
Now for first wedge momentum conservation and from energy conswrvation,
0 + 0 = mv1 - Mv2
we get v2 = mv1/M m/s.
and
mgh = 0.5Mv2^2 + 0.5mv1^2
solving both we get
v1^2 = 2Mgh/(M+m) …..................(1)
For wedge (2)
0.5mv1^2 = 0.5Mv0^2 + mgx
and
mv1 = Mv0
solving we get,
x = v1^2(M – m)/2gM
substituing from eq. (1)
we get
x = [(M-m)/(M+m)]h meter.