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`        The horizontal and vertical displacement a of a projectile are given by x=3tmetees and y=4t-5t^2metre. The initial velocity of projectile is options: 3 4 5 6`
one year ago

Arun
18691 Points
```							dx/dt = 3
dy/dt = 4 - 10t
In starting, t= 0
Hence dy/dt = 4
Hence initial velocity = sqrt(3²+4²) = sqrt(25) = 5 m/sec

Regards
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions