The horizontal and vertical displacement a of a projectile are given by x=3tmetees and y=4t-5t^2metre. The initial velocity of projectile is options: 3 4 5 6

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Arun · Answer

dx/dt = 3 dy/dt = 4 - 10t In starting, t= 0 Hence dy/dt = 4 Hence initial velocity = sqrt(3&sup2;+4&sup2;) = sqrt(25) = 5 m/sec Regards Arun (askIITians forum expert)

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The horizontal and vertical displacement a of a projectile are given by x=3tmetees and y=4t-5t^2metre. The initial velocity of projectile is options: 3 4 5 6

The horizontal and vertical displacement a of a projectile are given by x=3tmetees and y=4t-5t^2metre. The initial velocity of projectile is options: 3 4 5 6

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The horizontal and vertical displacement a of a projectile are given by x=3tmetees and y=4t-5t^2metre. The initial velocity of projectile is options: 3 4 5 6

The horizontal and vertical displacement a of a projectile are given by x=3tmetees and y=4t-5t^2metre. The initial velocity of projectile is options: 3 4 5 6

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