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`        The height of a mercury barometer is 75 cm at sea level and 50 cm at the top of a hill. Ratio of density of mercury to that of air is 10^4. The height of the hill isA)            250 m                                      B)            2.5 kmC)            1.25 km                                  D)            750 m`
one year ago

Arun
24483 Points
```							Dear student I am getting my answer as 2500 m or 2.5 km Hence option B is correct. RegardsArun (askIITians forum expert)
```
one year ago
Sahani Kumar
99 Points
```							Please explain me how you did it. Please plz........I want it's solution urgently. Sir I will be so much thankful to you.
```
one year ago
Sarang
38 Points
```							Pressure difference between sea level and the hill would bedP1 = dh1 X ρm X g  (1)where dh = h1 (sea level mercury height = 75 cm) - h2 (hill top mercury height = 50 cm) ρm is the density of mercury and  the pressure difference in atmospheric pressure would bedP2 = dh2 X ρa X g  (2)where dh2 is the height of the hill, ρa is the density of air now, we know that (1) = (2), so dh1 X ρm X g = dh2 X ρa X g by substituting appropriate values and rearranging, we get dh2 = 0.25 X  (ρm/ ρa) = 0.25 X 104 mor dh2 = 2500 m  thus, the height of the hill is dh2 = 2500m = 2.5 km
```
one year ago
Sarang
38 Points
```							B is correct answer Correct option B Explanation in answer 1Sorry for 2 answers …. Regards....Sarang
```
one year ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions