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Grade: 9

                        

The height at which the acceleration due to gravity becomes g/9 in terms of R, the radius of earth is? 1.2R 2.R/root2 3.R/2 4.root2/R

2 years ago

Answers : (1)

ManpreetK
32 Points
							a =g/9 Let a=g`g`= g/(1+h/R) ^2g/9 = g/(1+h/R)^21/9 = 1/(1+h/R)^29= (1+h/R)^23= (1+h/R)h/R = 2h=2R
						
2 years ago
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