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Lokesh kumar Grade: 6
        
The height at which the acceleration due to gravity becomes g/9 (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :
 
(a) R / v2
(b) R / 2
(c) v2 R
(d) 2 R
3 years ago

Answers : (2)

Deepak Patra
askIITians Faculty
474 Points
										

(d) We know that g’/g = R2/(R+h)2

? g/9/g = [R/R+h]2 ? h = 2R
3 years ago
Manas Satish Bedmutha
22 Points
										
By Newton’s law of gravitation, g is inversely proportional to r2,
So, g‘ / g = [R / R+h ] 2
Put g’ = g/9;  h= 2R
3 years ago
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