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The greatest acceleration or deceleration that a train may have is a .The minimum time in which the train may reach feom one station to the other seperated by a distance d is Ans-(4d/a) 1/2

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2 years ago

Bhanu Pratap
25 Points
```							The total distnace train has to cover is d.The first half it will accelerate and the second half it’ll deaccelerate, and it’ll take half-half time for both acceleration and deacceleration. Hence, d/2 = a/2(t/2)2               (u = 0 ,because the train was at rest initially)4d/a = t2t = (4da)½. ;)
```
2 years ago
Kaushki
19 Points
```							Sorry,but here it is not given that the train accelerate in half of total time.......................................?..........
```
2 years ago
Bhanu Pratap
25 Points
```							It is given that the train will either accelerate or deaccelerate i.e train cannot be in an uniform motion. the magnitude of acceleration and deacceleration is also same i.e a. Hence after accelerating for some time,the train will need the same amount of time to stop at the given retardation rate. u can”t increase or decrease the retardation rate, and hence u cannot decrease the time it”ll take to stop.
```
2 years ago
Aman Gupta
24 Points
```							But according to question we have to find the minimum time. At time will be minimum when the acceleration is high..... So we can't assume that it will decelerate half the way... If it will decelerate then the time would not be minimum???......
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions