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The forces 20N ,30N,40N,50N and 60N are acting at one of the angular points of a regular hexagon, towards the other five angular point , taken in order. Find the magnitude and direction of the resultant force.

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9 months ago

Arun
24738 Points
```							Dear student I have attached the image. Please go through it. And in case of any difficulty, please feel free to ask again. Regards
```
9 months ago
Vikas TU
12141 Points
```							Dear student Please follow the below link https://www.askiitians.com/forums/Mechanics/the-forces-20n-30n-40n-and-60n-are-acting-on-one_199951.htmGood Luck
```
9 months ago
aswanth nayak
100 Points
```							Dear Student,Please find the following solution, Summation of forces in x direction= 20 + 30 cos 30 + 40 Cos 60 - 60 Cos 60 = 35.98Animation of forces in wind direction is equal to 30 sin 30 + 40 sin 60 + 50 + 60 sin 60= 151.60Resultant of a force acting isR=√(fx)*(fx)+(fy)*(fy)R=155.80Alpha =tan(inverse(fy/fx))Alpha=76.64  Hope this helps youRegards
```
6 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions