×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The force between two inert gas atoms is often described by a function of the form F = Ar−^13 −Br−^7 where A and B are positive constants and r is the distance between the atoms. Answer in terms of A and B. (a) What is the equilibrium separation? (b) What is the work done if the atoms are moved from their equilibrium separation to a very large distance apart?


2 years ago

Quanta
13 Points
							at equilibrium sum of all forces is zero ,this means Ar^-13-Br-7=0now solve this for rfor the work done ,since the force is a function of r (ie it is a varing force ),so use the following equation $w=\int_{R}^{r}F.drcos\mathbb{\theta }$ here angle between force and dr s 180 ,r is the initial distance and R is the final maximum distance...after integration you would get

2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions