The equation [ P+a/v2].(v-b)= constant.The unit of 'a' is :- A) Dyne×cm5 B) Dyne×cm4 C) Dyne×cm3 D) Dyne×cm2

Question

Arun · Answer

Dear student Dimension of P = dimension of a/v² Dyne/cm² = dimension of a /(cm³)² Dimension of a = Dyne * cm³ * cm³ /cm² Dimension of a = Dyne * cm⁴ Regards Arun

Santhosh · Answer

The speed of light c, accleration a, due to gravity g, pressure p, are, taken, as, the, fundamental quantities, then, the, dimensions of gravitational of t is

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The equation [ P+a/v2].(v-b)= constant.The unit of 'a' is :- A) Dyne×cm5 B) Dyne×cm4 C) Dyne×cm3 D) Dyne×cm2

The equation [ P+a/v2].(v-b)= constant.The unit of 'a' is :-
A) Dyne×cm5
B) Dyne×cm4
C) Dyne×cm3
D) Dyne×cm2

2 Answers

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The equation [ P+a/v2].(v-b)= constant.The unit of 'a' is :- A) Dyne×cm5 B) Dyne×cm4 C) Dyne×cm3 D) Dyne×cm2

The equation [ P+a/v2].(v-b)= constant.The unit of 'a' is :-A) Dyne×cm5B) Dyne×cm4C) Dyne×cm3D) Dyne×cm2

2 Answers

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The equation [ P+a/v2].(v-b)= constant.The unit of 'a' is :-
A) Dyne×cm5
B) Dyne×cm4
C) Dyne×cm3
D) Dyne×cm2