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The elastic limit of steel is 8 × 108 N m-2 and its Young modulus 2 × 1011 N m-2. Find the maximum elongation of a half-meter steel wire that can be given without exceeding the elastic limit.complete answer
L ⇒ ∆L = (F/A)(L/y) y = FL/AL = (8*108)(0.5/2*1011)L = 2*10-3 mHope it clears............................................................................................................
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