The driver of a train running at 25m/s sights a train B moving in the same direction on the same track with 15m/s.Thedriver of the train ‘A’ applies breaks to produce decelaration of 1m/s 2 . what should be the minimum distace between the trains to avoid accident?

Question

Vikas TU · Answer

From first eqn. = 25 – 1*t t = 25 seconds. the Train A would stop. and distance it would cover in that time, 0^2 = 625 – 2*1*s s = 625/2 m = > 312.5 m. in that time, train would have covered, x = 15*25 = > 375 meter. The minimum distance should be=> 375 – 312.5 = 62.5 m.

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The driver of a train running at 25m/s sights a train B moving in the same direction on the same track with 15m/s.Thedriver of the train ‘A’ applies breaks to produce decelaration of 1m/s 2 . what should be the minimum distace between the trains to avoid accident?

The driver of a train running at 25m/s sights a train B moving in the same direction on the same track with 15m/s.Thedriver of the train ‘A’ applies breaks to produce decelaration of 1m/s². what should be the minimum distace between the trains to avoid accident?

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The driver of a train running at 25m/s sights a train B moving in the same direction on the same track with 15m/s.Thedriver of the train ‘A’ applies breaks to produce decelaration of 1m/s 2 . what should be the minimum distace between the trains to avoid accident?

The driver of a train running at 25m/s sights a train B moving in the same direction on the same track with 15m/s.Thedriver of the train ‘A’ applies breaks to produce decelaration of 1m/s2. what should be the minimum distace between the trains to avoid accident?

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The driver of a train running at 25m/s sights a train B moving in the same direction on the same track with 15m/s.Thedriver of the train ‘A’ applies breaks to produce decelaration of 1m/s². what should be the minimum distace between the trains to avoid accident?