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The distance moved by a body along a straight line is proportional to the square root of the time . It's acceleration in terms of velocity V of the body is
The distance moved by a body along a straight line is proportional to the square root of the time . It's acceleration in terms of velocity V of the body is


2 years ago

Susmita
425 Points
							Given$x=t^\frac{1}{2}$Velocity v=dx/dt                  $=\frac{d}{dt} t^\frac{1}{2}=\frac{1}{2\sqrt{t}}$So acceleration$a=\frac{d}{dt}v=\frac{-1}{4t\sqrt{t}}$                     $=\frac{-1}{2\sqrt{t}}(\frac{1}{2\sqrt{t}})^2�2$                     =-v.v2.2=-2v3Hope this helps.If it does please approve the answer.

2 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions