Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

THE DISPLACEMENT OF A PARTICLE STARTING from rest and moving under a constant acceleration is calculated by the formula S= 1/2 at^2 .if there occurs an error of 30% in the measurement of time interval , what error will be introduced in the calculation of S?

THE DISPLACEMENT OF A PARTICLE STARTING from rest and moving under a constant acceleration is calculated by the formula S= 1/2 at^2 .if there occurs an error of 30% in the measurement of time interval , what error will be introduced in the calculation of S?

Grade:12

4 Answers

AMRENDRA JHA
37 Points
7 years ago
40.82%
Harsh davda
41 Points
7 years ago
i think i answered this question didnt u get it..?
Harsh davda
41 Points
7 years ago
here S= 1/2at² but due to error put S+dS instead of S and t+dt instead of t (here d is delta) hence... S+dS=1/2a(t+dt)² =1/2a(t²+2tdt+[dt]²) .... here S=1/2at² hence they get cancelled out... we get here is dS=atdt+1/2a[dt]².....divide it by S=1/2at²...u would get dS/S=2dt/t+[dt/t]²...(1) it is given that dt/t=30/100=0.3 ... now put this in equation (1).. u would get dS/S=0.6+0.09=0.69=69% ... and that is the answer..
chaitnyakishore
26 Points
7 years ago
Given that (S= 1/2 at^2) and error is 30% S`=(1/2) a(30*t/100)^2 =(1/2)*a*0.09*t^2 S`=0.09S % error in S=(S-S`/S)*100 =((1-0.09)S/S)*100 =91%

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free