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`        The coin is dropped by a man standing in the lift, 1)When the lift is at rest, then it hit the floor in T1sec 2)When the lift is moving upward with acceleration =a,then it hit the floor in T2sec 3)When the lift is moving downward with acceleration =a,then it hit the floor in T3sec, then find out the relation between T1,T2 and T3.`
one year ago

Vikas TU
9794 Points
```								When the lift is at rest.h = 0 + 0.5gt1^2 	When the lift is accelearted by a upwards,h = 0 + 0.5(g+a)t2^2 	When the lift is accelerated downwards,h = 0 + 0.5(g – a)t3^2 From all the 3 equations if we relate we get,(g-a)t3^2 = (g+a)t2^2or(t2/t3)^2 = (g-a)/(g+a)t2/t3 = root(g-a/g+a) For t1, 0.5(g+a)t2^2 = 0.5g(t1^2)t1/t2 = root((g+a)/g) Hence these would all be the relations.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions