Vikas TU
Last Activity: 6 Years ago
- When the lift is at rest.
h = 0 + 0.5gt1^2
- When the lift is accelearted by a upwards,
h = 0 + 0.5(g+a)t2^2
- When the lift is accelerated downwards,
h = 0 + 0.5(g – a)t3^2
From all the 3 equations if we relate we get,
(g-a)t3^2 = (g+a)t2^2
or
(t2/t3)^2 = (g-a)/(g+a)
t2/t3 = root(g-a/g+a)
For t1,
0.5(g+a)t2^2 = 0.5g(t1^2)
t1/t2 = root((g+a)/g)
Hence these would all be the relations.