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Grade: 12th pass 
        
The coefficient of static friction between the tires of a car and a dry road is 0.62. The mass of the car is 1500 kg. What maximum braking force is obtainable (a) on a level road and (b) on an 8.6° downgrade?
2 years ago

Answers : (1)

Vishal Mehta
35 Points 
							u=.62, W=1500 (a) ∆=0° so F=uR=   uWcos∆=.62×1500×1=930 N(b) ∆=8.6° so F= uR+Wsin∆=uWcos∆+Wsin∆= W(ucos8.6+sin8.6)=1500(.62(-.67)+.73)=1500×1.14=1718.1N
2 years ago
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Course Features

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  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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