To find the average force that acted on the car during impact, we will use the impulse-momentum theorem, which states:
Impulse = Change in Momentum
Mathematically,
F_avg * Δt = m * Δv
where:
F_avg = Average force (to be determined)
Δt = Time duration of impact = 0.54 s
m = Mass of the car = 2300 kg
Δv = Change in velocity = Final velocity - Initial velocity
= 0 - 15 m/s
= -15 m/s
Now, solving for F_avg:
F_avg = (m * Δv) / Δt
F_avg = (2300 kg * (-15 m/s)) / 0.54 s
F_avg = (-34500 kg·m/s) / 0.54 s
F_avg = -63888.89 N
The negative sign indicates that the force is acting in the opposite direction to the motion of the car (deceleration).
Final Answer:
The average force that acted on the car during impact is 63888.89 N (opposite to the direction of motion).
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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