The body of mass 100 is tied to one end of a 2m long string. The other end of the string is at the centrre of the horizontal circle.The maximum revolution in one minute is 200.The maximum tensile strengthof the string is .

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Arun · Answer

m =200 gm =.2kg r = 2m ω=200 rev/min =20 ∏/3 rad /sec centrifugal force F = mω 2 r = .2 * (20 ∏/3) 2 * 2 =175.45 N

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The body of mass 100 is tied to one end of a 2m long string. The other end of the string is at the centrre of the horizontal circle.The maximum revolution in one minute is 200.The maximum tensile strengthof the string is .

The body of mass 100 is tied to one end of a 2m long string. The other end of the string is at the centrre of the horizontal circle.The maximum revolution in one minute is 200.The maximum tensile strengthof the string is .

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The body of mass 100 is tied to one end of a 2m long string. The other end of the string is at the centrre of the horizontal circle.The maximum revolution in one minute is 200.The maximum tensile strengthof the string is .

The body of mass 100 is tied to one end of a 2m long string. The other end of the string is at the centrre of the horizontal circle.The maximum revolution in one minute is 200.The maximum tensile strengthof the string is .

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