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Grade 11Mechanics

the body is relesesd from top of the tower of hight taken t seconds to reach the ground position of body is t/4 seconds is

Profile image of kankala madhuha
5 Years agoGrade 11
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To understand the motion of a body released from the top of a tower, we need to consider the principles of free fall under the influence of gravity. When an object is dropped from a height, it accelerates downwards due to gravity, which is approximately 9.81 m/s² on Earth. Let's break down the scenario you've described.

Understanding Free Fall

When a body is released from a height, it starts with an initial velocity of zero and accelerates downward. The distance it travels can be calculated using the formula:

  • d = ut + (1/2)gt²

In this equation:

  • d is the distance fallen (height of the tower),
  • u is the initial velocity (0 m/s for a dropped object),
  • g is the acceleration due to gravity (approximately 9.81 m/s²),
  • t is the time in seconds.

Calculating the Height of the Tower

Since the initial velocity (u) is zero, the formula simplifies to:

  • d = (1/2)gt²

Now, if the body takes t seconds to reach the ground, we can substitute g with 9.81 m/s²:

  • d = (1/2)(9.81)t²

This gives us the height of the tower in terms of time. If you want to find the height after a specific time, just plug in the value of t.

Position of the Body at t/4 Seconds

Now, to find the position of the body at t/4 seconds, we can use the same formula:

  • d = (1/2)g(t/4)²

Substituting g again:

  • d = (1/2)(9.81)(t/4)²

Calculating this gives:

  • d = (1/2)(9.81)(t²/16)
  • d = (9.81t²)/32

This result tells you how far the body has fallen after t/4 seconds. It’s important to note that the body has not yet reached the ground at this point, as it takes a total of t seconds to do so.

Visualizing the Motion

Think of it like this: if you drop a ball from a tall building, it starts slow and speeds up as it falls. At t/4 seconds, it has only traveled a fraction of the total height, specifically about one-sixteenth of the total distance it will cover in t seconds. This illustrates how acceleration affects the distance traveled over time.

In summary, by applying the equations of motion, we can determine both the height of the tower and the position of the body at any given time during its fall. This understanding is crucial in physics, particularly in kinematics, where we analyze the motion of objects under various forces.