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The acceleration a of body moving with initial velocity u changes with distance x as a=k^2 root x where k is a positive constant. The distance travelled by the body when its velocity becomes 2u is

Anonymous , 8 Years ago
Grade 11
anser 2 Answers
Ritayan Chakrabarti
The answer is (3u/2k)⅔ this u can get by the integration of the givenformula. U see, a=k²√x so V= 2/3k²yx²/³ where y=dt/dx
Last Activity: 7 Years ago
Ritayan Chakrabarti
As fr ritayan, the y is considerdd to be equal to 1 fr constructive purposee.
Last Activity: 7 Years ago
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