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the accelaration of a particle moving in a straight line depends on its velocity as a=-v(ln(2^(1/2)). the time interval where velocity becomes half of its value at beginning is? 1sec 2 sec 3 sec or 4 sec
the accelaration of a particle moving in a straight line depends on its velocity as a=-v(ln(2^(1/2)). the time interval where velocity becomes half of its value at beginning is?1sec 2 sec 3 sec or 4 sec

```
4 years ago

Vikas TU
14146 Points
```							Given,a=-v(ln(2^(1/2))a = – (2.303v/2)*log2 = > -0.3vdv/v = – 0.3dtinetegerating both sides we get,logv  – log(v/2) = – 0.3t-log2 = -0.3tt = 1 sec.
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions