Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
the accelaration of a particle moving in a straight line depends on its velocity as a=-v(ln(2^(1/2)). the time interval where velocity becomes half of its value at beginning is? 1sec 2 sec 3 sec or 4 sec
Given,a=-v(ln(2^(1/2))a = – (2.303v/2)*log2 = > -0.3vdv/v = – 0.3dtinetegerating both sides we get,logv – log(v/2) = – 0.3t-log2 = -0.3tt = 1 sec.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -