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the accelaration of a particle moving in a straight line depends on its velocity as a=-v(ln(2^(1/2)). the time interval where velocity becomes half of its value at beginning is?1sec 2 sec 3 sec or 4 sec
the accelaration of a particle moving in a straight line depends on its velocity as a=-v(ln(2^(1/2)). the time interval where velocity becomes half of its value at beginning is?
1sec 2 sec 3 sec or 4 sec
Given,a=-v(ln(2^(1/2))a = – (2.303v/2)*log2 = > -0.3vdv/v = – 0.3dtinetegerating both sides we get,logv – log(v/2) = – 0.3t-log2 = -0.3tt = 1 sec.
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