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        The accelaration of a particle is increasing linearly with time t as bt. The particle starts from the origin with an intial velocity vo. The distance travelled at time t is
one month ago

Arun
24712 Points
							Given the acceleration as a function of time: a(t)=bt Integrate to obtain the velocity as a function of time.v(t)={\frac{1}{2}}bt^2+C   We are told that the constant of integration is V0 v(t)={\frac{1}{2}}bt^2+V_{0} Integrate, again, to obtain the displacement as a function of time.d(t)=16bt^3+V_{0}t+c The phrase "starts from the origin" tells us that the integration constant is 0: d(t)=16bt^3+V_{0}t

one month ago
Saurabh Koranglekar
8227 Points


one month ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions