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```
the accelaration of a particle is a=-4t if initially velocity is 8m/s the total distance covered by the particle till it comes to rest
the accelaration of a particle is a=-4t if initially velocity is 8m/s the total distance covered by the particle till it comes to rest

```
3 years ago

Shailendra Kumar Sharma
188 Points
```							a=-4tdv/dt =-4t => v=-2t2+c @ t=0 v=8 that gives c=8 so v= -2t2+8, this particle will be at rest i.e. v= 0 t=2secSonow distacne ds/dt= v =-2t2+8s=-2t3/3+8t+Kdistance traveled before coming rest is s(2)-s(0) =-16/3+16+K -K =32/3 =10.66m
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions