the accelaration of a particle is a=-4t if initially velocity is 8m/s the total distance covered by the particle till it comes to rest

Question

Shailendra Kumar Sharma · Answer

a=-4t
dv/dt =-4t => v=-2t2+c @ t=0 v=8 that gives c=8
so v= -2t²+8, this particle will be at rest i.e. v= 0
t=2sec

So
now distacne ds/dt= v =-2t²+8
s=-2t³/3+8t+K

distance traveled before coming rest is s(2)-s(0) =-16/3+16+K -K =32/3 =10.66m

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the accelaration of a particle is a=-4t if initially velocity is 8m/s the total distance covered by the particle till it comes to rest

the accelaration of a particle is a=-4t if initially velocity is 8m/s the total distance covered by the particle till it comes to rest

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the accelaration of a particle is a=-4t if initially velocity is 8m/s the total distance covered by the particle till it comes to rest

the accelaration of a particle is a=-4t if initially velocity is 8m/s the total distance covered by the particle till it comes to rest

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