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# The 4 kN force is applied at point a. Compute the moment of F about point O. Determine the coordinates of the point on x and y axes about which the moment of F is zero.

Marwan Alam
28 Points
one month ago
To find the moment of force we have to know three parameters, F, r, and angle between them. to find the r we have two points that passes through moment of arm r. i.e O(0,0) and A(1.2, 1.5) we can find r from formula of distance between two points which gives us 1.92m. Next we have to find the angle between the force and moment of arm r, for this we will use the small triangle given in the graph. using tan of angle to find the angle with x-axis. tan.angle=3/5 = 30.96. now extend the line of force backward and cross the moment of arm r. In clockwise direction from r to F the first angle is 30.96 so subtract this from 180 we get 149 degree. now put the data in the equation of moment = 1.92m x 4000x sin149 = 3955 N.m .
Marwan Alam
28 Points
one month ago
To find the moment of force we have to know three parameters, F, r, and angle between them. to find the r we have two points that passes through moment of arm r. i.e O(0,0) and A(1.2, 1.5) we can find r from formula of distance between two points which gives us 1.92m. Next we have to find the angle between the force and moment of arm r, for this we will use the small triangle given in the graph. using tan of angle to find the angle with x-axis. tan.angle=3/5 = 30.96. now extend the line of force backward and cross the moment of arm r. In clockwise direction from r to F the first angle is 30.96 so subtract this from 180 we get 149 degree. now put the data in the equation of moment = 1.92m x 4000x sin149 = 3955 N.m .
the moment will be zero about the point where the force is applied i.e point A(1.2, 1.3) because at this point the moment of arm r is zero.

Vibekjyoti Sahoo
145 Points
10 days ago
To find the moment of force we have to know three parameters, F, r, and angle between them. to find the r we have two points that passes through moment of arm r. i.e O(0,0) and A(1.2, 1.5) we can find r from formula of distance between two points which gives us 1.92m. Next we have to find the angle between the force and moment of arm r, for this we will use the small triangle given in the graph. using tan of angle to find the angle with x-axis. tan.angle=3/5 = 30.96. now extend the line of force backward and cross the moment of arm r. In clockwise direction from r to F the first angle is 30.96 so subtract this from 180 we get 149 degree. now put the data in the equation of moment = 1.92m x 4000x sin149 = 3955 N.m .
the moment will be zero about the point where the force is applied i.e point A(1.2, 1.3) because at this point the moment of arm r is zero.
Thank You