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Ten particle each of mass 1Kg,2Kg.....10Kg are placed 1m apart from each other. The Moment of Inertia of the system about an axis passsing through 5kg mass and perpendicular to the line joining the masses is?

```
3 years ago

Shailendra Kumar Sharma
188 Points
```							wrt to 5 we have to calculate the momentÂ ofÂ inertiaÂ (M.I)Â the distanceÂ of each ofÂ themÂ from 5Â  Â 4kg 1m,3kgÂ 2m,2kg 3 m,1kg 4 m,6kg 1m,7kg 2m,8kg 3m,9kg 4m,10kg 5mso M.I =10*25+9*24+8*9+7*4+6+5*0+4+3*4+2*9+1*16 =622 kgm2Â
```
3 years ago
Ritik
55 Points
```							:( Itâ€™s answer is 550 Kgm^2. But i dont know how to solve it. please help me....................it will be great help.
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions