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Ten particle each of mass 1Kg,2Kg.....10Kg are placed 1m apart from each other. The Moment of Inertia of the system about an axis passsing through 5kg mass and perpendicular to the line joining the masses is?

Ten particle each of mass 1Kg,2Kg.....10Kg are placed 1m apart from each other. The Moment of Inertia of the system about an axis passsing through 5kg mass and perpendicular to the line joining the masses is?

Grade:12th pass

2 Answers

Shailendra Kumar Sharma
188 Points
6 years ago
wrt to 5 we have to calculate the moment of inertia (M.I) 
the distance of each of them from 5   
4kg 1m,
3kg 2m,
2kg 3 m,
1kg 4 m,
6kg 1m,
7kg 2m,
8kg 3m,
9kg 4m,
10kg 5m
so M.I =10*25+9*24+8*9+7*4+6+5*0+4+3*4+2*9+1*16 =622 kgm2
 
Ritik
55 Points
6 years ago
:( It’s answer is 550 Kgm^2. But i dont know how to solve it. please help me....................
it will be great help.

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