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sumof two forces at a point is 16N.IF THE RESULTANT IS NORMAL TO SMALLER FORCE AND HAVE A MAGN ITUDE 8N. the two forces are ? 6 and 10n how

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6 years ago IIT Delhi
174 Points
```							assume smaller force is fsand larger force is fl and resultant is fr. as given in the question, when we will form the parallelogram the let acute angle between fs and fl is theta. so these two eqns will be formed-fs=fl*cos(theta)...1fr=fi*sin(theta)...2fs+fl=16...3 fr=8from 3 and 1-16=fl(1+cos(theta))...4by 2/4 0.5=sin(theta)/1+cos(theta).5=2sin(theta/2)*cos(theta/2)/2cos^2(theta/2)0.5=tan(theta/2)theta=2tan^-1(.5)=tan^-1(2*.5/1-.25)=>tan(theta)=4/3sin(theta)=4/5cos(theta)=3/5so fl=8*5/4=10N and fs=6Nsher mohammadb.tech iit delhifaculty, askiitians
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6 years ago
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