Starting from rest a wooden block moves with a velocity of 25ms^-1 along a rough ground and comes to rest. Calculate the distance travelled by the wooden block in the rough surface of coefficient of friction 0.25 .

Question

Arun · Answer

Initial velocity, u=10ms −1 Displacement, s=50m Final velocity, v=0 Acceleration of friction, a=μg=10μms −2 Apply second kinematic equation of motion, v 2 −u 2 =2as 0−10 2 =2(−10μ)×50 μ=0.1 Hence, coefficient of friction is 0.1

Vikas TU · Answer

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Starting from rest a wooden block moves with a velocity of 25ms^-1 along a rough ground and comes to rest. Calculate the distance travelled by the wooden block in the rough surface of coefficient of friction 0.25 .

Starting from rest a wooden block moves with a velocity of 25ms^-1 along a rough ground and comes to rest. Calculate the distance travelled by the wooden block in the rough surface of coefficient of friction 0.25 .

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Starting from rest a wooden block moves with a velocity of 25ms^-1 along a rough ground and comes to rest. Calculate the distance travelled by the wooden block in the rough surface of coefficient of friction 0.25 .

Starting from rest a wooden block moves with a velocity of 25ms^-1 along a rough ground and comes to rest. Calculate the distance travelled by the wooden block in the rough surface of coefficient of friction 0.25 .

2 Answers

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