Starting a race , 68.2 kgsprinter runs the first 7.04 m in 1.60 sec, starting from the restand accelerating uniformly.(A)what is the sprinter speed at the end of 1.60s?(B)what is the sprinter k.E . ?(C)what is the average power does the sprinter generate during the 1.60 s unterval?
Amama , 6 Years ago
Grade 12th pass
1 Answers
Arun
Last Activity: 6 Years ago
Dear student
(A)
s=0.5 a t^2
7.04=0.5 a 1.6^2
a=5.5
v=at
v=5.5*1.6
.
v=8.8 m/s
(B)
K.E=0.5mv^2
K.E=0.5*68.2*(5.5*t)^2
K.E=11346.775 * t^2 J
at any time t
(C)
P=m*a*s/t
P=68.2*5.5*7.04/1.6
P=1650.44 J/s
Regards
Arun (askIITians Forum expert)
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