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`        Starting a race , 68.2 kgsprinter runs the first 7.04 m in 1.60 sec, starting from the rest  and accelerating uniformly.(A)what is the sprinter speed at the end of 1.60s?(B)what is the sprinter k.E . ?(C)what is the average power does the sprinter generate during the 1.60 s unterval?`
one year ago

Arun
23359 Points
```							Dear student  (A)  s=0.5 a t^2 7.04=0.5 a 1.6^2 a=5.5 v=at v=5.5*1.6.v=8.8 m/s  (B)    K.E=0.5mv^2   K.E=0.5*68.2*(5.5*t)^2   K.E=11346.775 * t^2 J          at any time t (C)  P=m*a*s/t P=68.2*5.5*7.04/1.6P=1650.44 J/s    RegardsArun (askIITians Forum expert)
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions