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Grade 11Mechanics

Startind from the origin a body oscilates simple harmonic with a period of 2s after what time will it`s kE energy be75% of total energy

Nirup

9 Years agoGrade 11

1 Answer

DR STRANGE

9 Years ago

Hi,

K.E = (Total energy)*(1-x²) …......(considering amplitude to be 1)

where x is distance from origin

K.E. = 75%Total energy = ¾ total energy

1-x²=3/4

x=1/2

now , $x = \sin \omega t$ …...(oscillation starts from origin)

And

$\omega =\frac{2\pi }{T}$

Given T=2sec

$\frac{1}{2}=\sin \frac{2\pi }{T}t=\sin \frac{2\pi }{2}t=\sin \pi t$

Hence t= 1/6 sec... it will take 1/6 sec.

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