bramashini
Last Activity: 6 Years ago
Mg=2Rsin37
R=Mg/2sin37
R=Mg / 2*3/5 ( sin 37=3/5 is given)
therefore , R=5Mg/6
this sphere is lying between 2 inclined planes so there are 2 normal reactions on the sphere by the plane. if we resolve these reactions the vertical forces will be Rsin37*2 this system is under equllibrium so verical forces 2Rsin37 is equal to weight of the sphere Mg (here assume normal reaction= R)