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Grade 11Mechanics

speed of a projectile at its maximum height is root3/2 times its initial speed.if range of projectile is p times the maximum height attained by it,then p=

Profile image of siri gudipati
9 Years agoGrade 11
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1 Answer

Profile image of sunny
9 Years ago

total range is 2u2sin2∂/g

maximum height is 2u2sin2∂/g.

velocity t max.height is vcos∂.on comparing with question ∂=30.

2u2sin2∂/g    ×P=2u2sin2∂/g

now find P