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Grade: 11
        
solve for x:
2x3+3x2+x-30=0
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10 months ago

Answers : (2)

Ravneet
104 Points
							
step 1: by hit and trial, put some integers like 1,2,-1and-2 in the given equation 
RESULT: if we put 2 in the given equation, it will give us zero in RHS side, so we can say that 2 is the root of the cubic equation 
                   or (x-2) is the factor of equation 
step 2 :  now divide the cubic equation by its factor (x-2) , we will get quotient as 2x2 + 7x + 15 and remainder will be 0 . 
step 3 : (x-2)(2x2 + 7x + 15 ) = 2x3 + 3x2 + x -30 
step 4 : now solve the quadratic equation and you will get three factors or three vaue of x 
                NOTE: roots may be imaginary or real
10 months ago
Ankit kumar jha
28 Points
							
Just use hit and trial method to obtain at least one zero of the equation. Here we get 2 as one of its solutions. Then x-2 is a factor of the  given equation. You wiil get 2x^2+7x+15 as its quotient
. Factorise the quotient you will get another roots. 
10 months ago
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