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Six particles situated at the corners of a regular hexagon of side a move at a constant speed v. Each particle maintains a direction towards the particle at the next corner. Calculate the time the particles will take to meet each other ?


6 years ago

Vikas TU
12133 Points
							total time  = a/v + 2a/v + 3a/v + 4a/v + 5a/v

6 years ago
vinayaka
10 Points
							@ vikas Kumar Yadav... you are not be an IITan... a never mind... now, Initial separation between two particles=Side of hexagon=aFinal separation=0Therefore,Relative displacement between two particles=aParticle B has a component v cos 600 along particle BC (a side)Therefore, relative velocity with which B and C approaches each other=v- vcos60=v/2Since, v is constant, thus time taken by these two balls to meet each other is given by=(Relative displacement) / Relative velocity=a/(v/2)=2a/vSo, the time taken by the particles to meet each other=2a/v

5 years ago
vinayaka
10 Points
							Relative velocity of A wrt B = V - Vsin30 = V/2Time = distance / speed Time = 2a/VIn reality each particle will follow a curved path and eventually meet at the center of the hexagon.

5 years ago
Taral Jain
39 Points
							How to Sketch figure of this problem.Please clear its figure.How to think about this type of problems.

3 years ago
ankit singh
480 Points
							 along particle BC (a side)Therefore, relative velocity with which B and C approaches each other=v- vcos60=v/2Since, v is constant, thus time taken by these two balls to meet each other is given by=(Relative displacement) / Relative velocity=a/(v/2)=2a/vSo, the time taken by the particles to meet each other=2a/v600nitial separation between two particles=Side of hexagon=aFinal separation=0Therefore,Relative displacement between two particles=aParticle B has a component v cos

one month ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions