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Grade: 12th pass
        Six particles situated at the corners of a regular hexagon of side `a` move at a constant speed `v`. Each particle maintains a direction towards the particle at the next corner. Calculate the time the particles will take to meet each other ?
6 years ago

Answers : (4)

Vikas TU
11142 Points
							total time  = a/v + 2a/v + 3a/v + 4a/v + 5a/v
						
6 years ago
vinayaka
10 Points
							
@ vikas Kumar Yadav... you are not be an IITan... a never mind...
 
now, 
Initial separation between two particles=Side of hexagon=a
Final separation=0
Therefore,
Relative displacement between two particles=a
Particle B has a component v cos 
600 along particle BC (a side)
Therefore, relative velocity with which B and C approaches each other=v- vcos60
=v/2
Since, v is constant, thus time taken by these two balls to meet each other is given by
=(Relative displacement) / Relative velocity
=a/(v/2)=2a/v
So, the time taken by the particles to meet each other=2a/v
 
 
5 years ago
vinayaka
10 Points
							
Relative velocity of A wrt B = V - Vsin30 = V/2
Time = distance / speed Time = 2a/V
In reality each particle will follow a curved path and eventually meet at the center of the hexagon.
5 years ago
Taral Jain
39 Points
							How to Sketch figure of this problem.Please clear its figure.How to think about this type of problems.
						
3 years ago
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