Grade 12Mechanics

Six forces lying in a plane and forming angles of 60 relative to one another are applied to the centre of homogeneous sphere with mass M is equals to 6 kg. These forces are radially outward and consecutively 1N,2N,3N,4N,5N and6N. The acceleration of s p h e r e is

Kkr

7 Years agoGrade 12

2 Answers

Hemanth

7 Years ago

Hello Kkr,

here is the answer,

As all the forces are consecutive and are at angle of 60 degrees, They form as the sides from the center to the vertices of a regular hexagon.

If you do so , you’ll find that the vectors of magnitude (1,4), (2,5) and (3,6) are opposite (aligned at 180 degrees)

Finding their resultant, Three consecutive vectors of magnitude 3 and aligned at 60 degrees are formed.

Now at last finding their resultant , we get a vector of magnitude ‘6’ units

therefore, acceleration = Force /mass it implies

acceleration=6/6=1 m/s. That’s it

Khimraj

7 Years ago

try to resolve force in opposite direction

then resultant will have three force each of 3N at 0^o, 60^o, 120^o

then resulatnt of it will have two force of 3N and 3 $\sqrt{3}$ at angle 90

then resultant will be $\sqrt{(3\sqrt{3})^{2} + 3^{2}} = 6N$

Then acceleration = 6/6 = 1m/s²

Hope it clears.................................

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Six forces lying in a plane and forming angles of 60 relative to one another are applied to the centre of homogeneous sphere with mass M is equals to 6 kg. These forces are radially outward and consecutively 1N,2N,3N,4N,5N and6N. The acceleration of s p h e r e is

Kkr

2 Answers

Hemanth

Khimraj

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