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```
Sir,The final velocity of a particle falling freely under gravity is given by V^2-u^2=2gx where x is the distance covered. If V=18kmph g=1000cms^-2 x=120cm the u = ms^-1
Sir,The final velocity of a particle falling freely under gravity is given by V^2-u^2=2gx where x is the distance covered. If V=18kmph g=1000cms^-2 x=120cm the u =         ms^-1

```
4 years ago

Vikas TU
14149 Points
```							Just put all the values simply to get the value of u.Therefore,V^2 – u^2 = 2*g*x(18 * 1000 * 100/60*60)^2 = u^2 + 2*1000*120u^2 = 250000 – 240000     u^2 = 10,000 u =  100 cm/s
```
4 years ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions