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Grade: 12
        
sinx.log(sinx)dx=log2-1
Limit of integration:0 to pi/2
8 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
2304 Points
							Dear student

Please ask a question
8 months ago
Phanindra
226 Points
							
Put sinx = t... (1)then limits also will change...
Lower limit = 0 and upper limit = 1 
Now.. differentiate (1) that is cosxdx=dt  so..
dx = dt/cosx = dt/\sqrt{}(1-t^2)… 
Because ...sin2x + cos2x = 1...cosx = \sqrt{}(1-t^2)
Now the question chages and its limits are...0 and 1...
Hope you have understood the steps...
This is the procedure...
You will get the answer..
If you do not get the answer..then tell me.i will send the full solution..
 
 
8 months ago
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