×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Show that the maximum range of a projectile having an initial speed u is obtained when projected at an angle of 45 to the horizontal.
Show that the maximum range of a projectile having an initial speed u is obtained when projected at an angle of 45 to the horizontal.


3 years ago

Arun
25768 Points
							Dear Student As we knowRange R = u² sin2$\LARGE \theta$/gNow for maximum rangeSin2$\large \theta$ = 1Hence2$\large \theta$ = 90°$\large \theta$= 45° Hence angle should be 45° for maximum range. RegardsArun (askIITians forum expert)

3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions