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Show that the maximum range of a projectile having an initial speed u is obtained when projected at an angle of 45 to the horizontal. Show that the maximum range of a projectile having an initial speed u is obtained when projected at an angle of 45 to the horizontal.
Dear Student As we knowRange R = u² sin2/gNow for maximum rangeSin2 = 1Hence2 = 90°= 45° Hence angle should be 45° for maximum range. RegardsArun (askIITians forum expert)
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