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Select the correct answers A particle is projected vertically upwards in vacuum with a speed u. Then A) When it rises to half its maximum height, its speed becomes u/2.B)When it rises to half its maximum height, its speed becomes u√2C)The time taken to rise to half its maximum height is half the time taken to reach its maximum height.D)the time taken to rise to three-fourth of its maximum height is half the time taken to reach its Maximum height

Harsh Lokhande , 6 Years ago
Grade 11
anser 1 Answers
Eshan

Last Activity: 6 Years ago

Dear student,

Maximum height=\dfrac{u_y^2}{2g}
Time taken to reach maximum height=t_0=\dfrac{u_y}{g}

For motion from groudn to 3/4th the maximum height,

\dfrac{3}{8}\dfrac{u_y^2}{g}=u_yt-\dfrac{1}{2}gt^2
\implies t=\dfrac{u_y}{2g}=\dfrac{t_0}{2}

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