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Select the correct answers A particle is projected vertically upwards in vacuum with a speed u. Then A) When it rises to half its maximum height, its speed becomes u/2. B)When it rises to half its maximum height, its speed becomes u√2 C)The time taken to rise to half its maximum height is half the time taken to reach its maximum height. D)the time taken to rise to three-fourth of its maximum height is half the time taken to reach its Maximum height
Select the correct answers A particle is projected vertically upwards in vacuum with a speed u. Then A) When it rises to half its maximum height, its speed becomes u/2.B)When it rises to half its maximum height, its speed becomes u√2C)The time taken to rise to half its maximum height is half the time taken to reach its maximum height.D)the time taken to rise to three-fourth of its maximum height is half the time taken to reach its Maximum height

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2 years ago

Eshan
2095 Points
```							Dear student,Maximum height=$\dpi{80} \dfrac{u_y^2}{2g}$Time taken to reach maximum height=$\dpi{80} t_0=\dfrac{u_y}{g}$For motion from groudn to 3/4th the maximum height,$\dpi{80} \dfrac{3}{8}\dfrac{u_y^2}{g}=u_yt-\dfrac{1}{2}gt^2$$\dpi{80} \implies t=\dfrac{u_y}{2g}=\dfrac{t_0}{2}$
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions