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Rigid massless rod of length L joins two particles each of mass M the rod lies on a frictionless table and is struck by a particle of mass M and velocity V0 moving as shown .
After the collision the particle moves straight back. Find the angular velocity of system of point masses after collision assuming that the mechanical energy is conserved

Isha Joshi , 4 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To solve this problem, we need to analyze the collision and the subsequent motion of the system consisting of the two masses connected by a rigid rod. The key points to consider are the conservation of momentum and the conservation of mechanical energy, as well as the relationship between linear and angular velocity.

Understanding the System

We have a rigid, massless rod of length L connecting two particles, each with mass M. Initially, a third particle of mass M is moving towards the system with a velocity V0. Upon collision, this particle reverses direction and moves straight back. Our goal is to find the angular velocity of the system after the collision.

Conservation of Momentum

Before the collision, the momentum of the incoming particle is:

  • Initial momentum = MV0 (in the direction of the incoming particle)

After the collision, the incoming particle moves back with velocity -V0, and the two masses connected by the rod will start rotating about their center of mass. The total momentum after the collision can be expressed as:

  • Final momentum = -MV0 + 2MV (where V is the linear velocity of the center of mass of the two masses)

Setting the initial momentum equal to the final momentum gives us:

MV0 = -MV0 + 2MV

Rearranging this equation, we find:

2MV = 2MV0

Thus, the linear velocity V of the center of mass after the collision is:

V = V0

Finding Angular Velocity

Next, we need to relate the linear velocity of the masses to their angular velocity. The angular velocity (ω) can be found using the formula:

ω = V / r

In our case, r is the distance from the center of mass to either mass. Since the two masses are at the ends of the rod, the center of mass is located at L/2 from either mass. Therefore, we can substitute r with L/2:

ω = V / (L/2) = 2V / L

Substituting V = V0 into this equation gives us:

ω = 2V0 / L

Final Result

Thus, the angular velocity of the system of point masses after the collision is:

ω = 2V0 / L

Summary

In summary, we used the principles of conservation of momentum and the relationship between linear and angular velocity to determine the angular velocity of the system after the collision. The key steps involved calculating the linear velocity of the center of mass and then relating it to the angular velocity using the distance from the center of mass to the masses. This approach illustrates how fundamental physics principles can be applied to analyze dynamic systems effectively.

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