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Grade 11Mechanics

Respected sir.
When a ball is thrown up,time taken to reach the max. height and, time taken to reach the ground back will be equal, but why ?

Profile image of KINSUK DE
7 Years agoGrade 11
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1 Answer

Profile image of Khimraj
ApprovedApproved Tutor Answer7 Years ago
Lets understand mathematically
lets thrown velocity is u
then
to reach max height
0 = u -gt1
then t1 = u/g
and max height = u2/2g
for its return journy
h = u2/2g = ½*g*t22
then t2 = u/g.
so t1 = t2
Hope it clears.