Flag Electric Current> ram and shyam are walking on two perpendi...
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ram and shyam are walking on two perpendicular tracks with speed 3m/s n 4m/s respectively.At a certain moment (say t=0) ram n shyam are at 20m n 40m away from the intersection of tracks respectively n moving towards the intersection of the tracks.
Q.1>find magnitude of velcity of ram with respect to shyam.(got the ans)
Q2.>shortest distance btwn them subsequently is
18m 15m 25m 8m
Q.3> the time they are at shortest distance from each other subsequently is
8.8s 12s 15s 44s

how do i get Q2 n 3....if Q2 is solved then perhaps 3rd can also be solved

Aditi Chauhan , 12 Years ago
Grade 10
anser 1 Answers
Askiitians Tutor Team

To tackle the problem involving Ram and Shyam walking on perpendicular tracks, we first need to analyze their movements and the distances involved. Let's break it down step by step to find the shortest distance between them and the time at which this occurs.

Understanding Their Movements

Ram is walking towards the intersection at a speed of 3 m/s, starting from a distance of 20 m. Shyam is moving towards the same intersection at a speed of 4 m/s, starting from 40 m away. Since they are on perpendicular tracks, we can visualize their paths as forming a right triangle, where the intersection is the right angle.

Position Equations

We can express their positions as functions of time:

  • Position of Ram at time t: x_R(t) = 20 - 3t
  • Position of Shyam at time t: y_S(t) = 40 - 4t

Finding the Shortest Distance

The distance between Ram and Shyam at any time t can be represented using the Pythagorean theorem:

D(t) = √((x_R(t))² + (y_S(t))²)

Substituting the position equations into the distance formula gives us:

D(t) = √((20 - 3t)² + (40 - 4t)²)

Expanding the Distance Formula

Let's expand this expression:

  • D(t) = √((20 - 3t)² + (40 - 4t)²)
  • = √((400 - 120t + 9t²) + (1600 - 320t + 16t²))
  • = √(400 + 1600 - 120t - 320t + 25t²)
  • = √(2000 - 440t + 25t²)

Minimizing the Distance

To find the shortest distance, we need to minimize D(t). This can be done by minimizing the square of the distance, D²(t), which simplifies our calculations:

D²(t) = 2000 - 440t + 25t²

To find the minimum, we can take the derivative and set it to zero:

d(D²)/dt = -440 + 50t = 0

Solving for t gives:

50t = 440 → t = 8.8 seconds

Calculating the Shortest Distance

Now, substituting t = 8.8 seconds back into the distance formula:

D(8.8) = √(2000 - 440(8.8) + 25(8.8)²)

Calculating this step-by-step:

  • D(8.8) = √(2000 - 3872 + 1936)
  • = √(64) = 8 m

Final Answers

From our calculations, we find:

  • For Q2, the shortest distance between Ram and Shyam is 8 m, which corresponds to option D.
  • For Q3, the time at which they are at the shortest distance is 8.8 seconds, which corresponds to option A.

This systematic approach allows us to derive both the shortest distance and the time at which it occurs by using their speed and initial positions effectively. If you have any further questions or need clarification on any part of the process, feel free to ask!

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