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R radius sphere moves continuously to a=g on a linear line .A single particles is placed on upper part of the sphere.It is free from discarded ( left and right) with sphere .without circular spacing sphere in the function of x speed of particles respect to the sphere.

Kamal patel , 7 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To understand the motion of a particle placed on the upper part of a sphere that is rolling along a linear path under the influence of gravity, we need to break down the problem into several components. This involves analyzing the forces acting on the particle, the motion of the sphere, and how these two interact.

Understanding the Sphere's Motion

The sphere, with radius R, is rolling along a straight line under the influence of gravitational acceleration, denoted as g. When a sphere rolls without slipping, its linear acceleration is related to its angular acceleration. The relationship can be described by the equation:

  • a = R * α

Here, a is the linear acceleration of the sphere, R is the radius, and α is the angular acceleration. Since the sphere is rolling down an incline or moving horizontally, we can assume that the gravitational force is acting on it, causing it to accelerate.

Particle Dynamics on the Sphere

Now, let’s focus on the particle placed at the top of the sphere. Initially, this particle has a gravitational force acting on it, which can be expressed as:

  • F_gravity = m * g

where m is the mass of the particle. As the sphere rolls, the particle experiences two main forces: the gravitational force pulling it downward and the normal force exerted by the surface of the sphere. The particle is free to move left or right relative to the sphere, which adds complexity to its motion.

Relative Motion of the Particle

As the sphere rolls, the particle will also experience a centripetal acceleration due to its circular path around the sphere. The centripetal acceleration can be described by:

  • a_c = v^2 / R

where v is the tangential speed of the particle relative to the sphere. The particle's speed will change based on its position on the sphere and the sphere's linear speed. If we denote the linear speed of the sphere as V, the total speed of the particle can be expressed as:

  • v_total = V + v

Here, v is the speed of the particle relative to the sphere. As the sphere rolls, the particle will tend to slide down due to gravity, but its motion will also be influenced by the sphere's acceleration.

Equations of Motion

To analyze the motion mathematically, we can set up equations based on Newton's second law. The net force acting on the particle can be expressed as:

  • F_net = m * a

Where a is the acceleration of the particle. The forces acting on the particle include the gravitational force and the component of the normal force acting along the direction of motion. As the sphere rolls, the particle will experience a downward force due to gravity and a centripetal force that keeps it on the sphere's surface.

Example Scenario

Imagine the sphere is rolling down a slope. As it accelerates, the particle at the top will begin to slide down the sphere due to gravity. The speed of the particle relative to the sphere will depend on how quickly the sphere is rolling and the gravitational pull acting on the particle. If the sphere rolls with a constant acceleration, the particle will eventually reach a point where it either rolls off or continues to move along with the sphere, depending on the forces at play.

Final Thoughts

In summary, the motion of the particle on the sphere is influenced by both the gravitational force and the sphere's linear motion. By applying the principles of dynamics and considering the forces acting on the particle, we can derive the equations that govern its motion. This scenario beautifully illustrates the interplay between linear and rotational motion, showcasing the complexities of physics in a dynamic system.

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